clock menu more-arrow no yes

Filed under:

Roman Abramovich's $75M Buy Would Shatter Co-op Record

New, 28 comments


Russian billionaire and unabashed whale Roman Abramovich already owns a crop of ginormous luxury properties in locales from London and the French Riviera to St. Barths and, because why not, London again. So why not add New York to the list? Why yes, yes, he did, according to the New York Post, which is reporting that he and partner Dasha Zhukova are in contract to buy the decadent mansion at 828 Fifth Avenue for a whopping $75 million. If it all goes through, that sale will positively shatter the record for the most expensive co-op purchase in the city, currently held by David Geffen's $54 million buy last year just a few blocks south at 785 Fifth Avenue.

Now back to the property at hand. Formerly owned by the Ronson family, the unit, made of three combined apartments, is a truly majestic beaut (no brokerbabble exaggeration necessary here): there are 22 rooms, eight bedrooms, and 10.5 bathrooms. Don't forget the grand ballroom, reception rotunda, gym, library, and rooftop terrace. Last time it was listed, the maintenance was a mere $38,201 a month. Worth the price tag?

· Listing: 28 Fifth Avenue [StreetEasy]
· Russian mogul pays record $75M for Fifth Avenue co-op [NYP]
· Fifth Avenue Mansion-in-Progress Officially Available for $72M [Curbed]
· Really Rich Family Gives Up Fifth Avenue Mansion Dreams [Curbed]
· All 828 Fifth Avenue coverage [Curbed]

828 Fifth Avenue

828 Fifth Avenue, New York, NY